Add dual isogeny

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Henry de Valence 2018-04-04 17:41:37 -07:00
parent 3f68349480
commit 25024a63bc

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@ -118,8 +118,14 @@ $$
$$
\theta\_{a,d} : (s,t) \mapsto \left( \frac{1}{\sqrt{ad-1}} \cdot \frac{2s}{t},\quad \frac{1+as\^2}{1-as\^2} \right).
$$
XXX Its dual is ... ?
Its dual is
$$
\hat{\theta}\_{a,d} : \mathcal E\_{a,d} \longrightarrow \mathcal J\_{a\^2, -a(a+d)/(a-d)},
$$
defined by
$$
\hat{\theta}\_{a,d} : (x,y) \mapsto \left( \sqrt{ad-1} \cdot \frac{xy}{1-ax\^2}, \frac{y^2 + ax^2}{1-ax^2} \right)
$$
The kernel of the isogeny is \\( \{(0, \pm 1)\} \\).
The image of the isogeny is \\(\[2\](\mathcal E)\\). To see this,
@ -134,10 +140,12 @@ $$
$$
To determine the image \\(\theta(\mathcal J[2])\\) of the
\\(2\\)-torsion, we consider the image of the coset \\(\theta((s,t)
+ \mathcal J[2])\\). Let \\((x,y) = \theta(s,t)\\); then
\\(\theta(-s,-t) = (x,y)\\) and \\(\theta(1/as, -t/as\^2) = (-x,
-y)\\), so that \\(\theta(\mathcal J[2]) = \mathcal E[2]\\).
\\(2\\)-torsion, we consider the image of the coset
\\(\theta((s,t) + \mathcal J[2])\\).
Let \\((x,y) = \theta(s,t)\\); then
\\(\theta(-s,-t) = (x,y)\\) and
\\(\theta(1/as, -t/as\^2) = (-x, -y)\\),
so that \\(\theta(\mathcal J[2]) = \mathcal E[2]\\).
The Decaf paper recalls that, for a group \\( G \\) with normal
subgroup \\(G' \leq G\\), a group homomorphism \\( \phi : G