Merge branch 'feature/montgomery-x-format_r1' into develop

This commit is contained in:
Isis Lovecruft 2017-03-04 05:48:12 +00:00
commit b81f84bee8
Failed to extract signature

View file

@ -112,13 +112,13 @@ impl Debug for CompressedEdwardsY {
impl CompressedEdwardsY {
/// View this `CompressedEdwardsY` as an array of bytes.
pub fn as_bytes<'a>(&'a self) -> &'a [u8;32] {
pub fn as_bytes<'a>(&'a self) -> &'a [u8; 32] {
&self.0
}
/// Copy this `CompressedEdwardsY` to an array of bytes.
/// XXX is this useful?
pub fn to_bytes(&self) -> [u8;32] {
pub fn to_bytes(&self) -> [u8; 32] {
self.0
}
@ -162,49 +162,115 @@ pub struct CompressedMontgomeryU(pub [u8; 32]);
impl CompressedMontgomeryU {
/// View this `CompressedMontgomeryU` as an array of bytes.
pub fn to_bytes(&self) -> [u8;32] {
pub fn to_bytes(&self) -> [u8; 32] {
self.0
}
/// Attempt to decompress to an `ExtendedPoint`.
///
/// Note that since there are two curve points with the same
/// # Note
///
/// Since there are two curve points with the same
/// `u`-coordinate, the `u`-coordinate does not fully specify a
/// point.
/// point. That is, roundtripping between an `ExtendedPoint` and
/// a `CompressedMontgomeryU` discards its sign bit.
///
/// XXX match behaviour in Signal specification re: sign choice
/// and rewrite this note
/// # Warning
///
/// XXX check for div by zero: when is u = -1 ?
/// XXX exceptional points for the birational map
/// This function is *not* constant time.
///
/// # Return
///
/// An `Option<ExtendedPoint>`, which will be `None` if either condition holds:
///
/// * `u = -1`, or
/// * `v` is not square.
//
// XXX any other exceptional points for the birational map?
pub fn decompress(&self) -> Option<ExtendedPoint> {
// u = (1 + y) / (1 - y)
// v = sqrt(-486664) * u / x
//
// so
//
// y = (u - 1) / (u + 1)
let u = FieldElement::from_bytes(&self.0);
let u: FieldElement = FieldElement::from_bytes(&self.0);
// If u = -1, then v^2 = u*(u^2+486662*u+1) = 486660.
// But 486660 is nonsquare mod p, so this is not a curve point.
//
// XXX what does Signal do here?
//
// Note: currently, without this check, u = -1 will accidentally
// decode to a valid (but incorrect) point, since 0.invert() = 0.
if u == FieldElement::minus_one() {
return None;
}
let u_plus_1_inv = (&u + &FieldElement::one()).invert();
let y = &(&u - &FieldElement::one()) * &u_plus_1_inv;
let y: FieldElement = CompressedMontgomeryU::to_edwards_y(&u); // y = (u-1)/(u+1)
// XXX this does two inversions: the above + one in .decompress()
// is it possible to do one?
CompressedEdwardsY(y.to_bytes()).decompress()
}
/// Given a Montgomery `u` coordinate, compute an Edwards `y` via
/// `y = (u-1)/(u+1)`.
///
/// # Return
///
/// A `FieldElement` corresponding to this coordinate, but in Edwards form.
fn to_edwards_y(u: &FieldElement) -> FieldElement {
// Since `u = (1+y)/(1-y)` and `v = √(u(u²+Au+1))`, so `y = (u-1)/(u+1)`.
&(u - &FieldElement::one()) * &(u + &FieldElement::one()).invert()
}
/// Given a Montgomery `u` coordinate, compute the corresponding
/// Montgomery `v` coordinate by computing the right-hand side of
/// the Montgomery field equation, `v² = u(u² + Au +1)`.
///
/// # Return
///
/// A tuple of (`u8`, `FieldElement`), where the `u8` is `1` if the v² was
/// actually a square and `0` if otherwise, along with a `FieldElement`: the
/// Montgomery `v` corresponding to this `u`.
fn to_montgomery_v(u: &FieldElement) -> (u8, FieldElement) {
let one: FieldElement = FieldElement::one();
let v_squared: FieldElement = u * &(&(&u.square() + &(&(&constants::A * u) + &one)));
let v_inv: FieldElement;
let v: FieldElement;
let okay: u8;
let (okay, v_inv) = v_squared.invsqrt();
let v = &v_inv * &v_squared;
(okay, v)
}
/// Given Montgomery coordinates `(u, v)`, recover the Edwards `x` coordinate.
///
/// # Inputs
///
/// * `u` and `v` are both `&FieldElement`s, corresponding the the `(u, v)`
/// coordinates of this `CompressedMontgomeryU`.
/// * `sign` is an &u8.
///
/// ## Explanation of choice of `sign`
///
/// ### Original Signal behaviour:
///
/// - `1u8` will leave `x` negative if it is negative, and will negate
/// `x` if it is positive, and
/// - `0u8` will leave `x` positive if it is positive, and will negate
/// `x` if it is negative.
///
/// Hence, if `sign` is `1u8`, the returned `x` will be negative.
/// Otherwise, if `sign` is `0u8`, the returned `x` will be positive.
///
/// # Return
///
/// A `FieldElement`, the Edwards `x` coordinate, by using `(u, v)` to
/// convert from Montgomery to Edwards form via the right-hand side of the
/// equation: `x=(u/v)*sqrt(-A-2)`.
fn to_edwards_x(u: &FieldElement, v: &FieldElement, sign: &u8) -> FieldElement {
let mut x: FieldElement = &(u * &v.invert()) * &constants::SQRT_MINUS_APLUS2;
let neg_x: FieldElement = -(&x);
let current_sign: u8 = x.is_negative_ed25519();
// Negate x to match the sign:
x.conditional_assign(&neg_x, current_sign ^ sign);
x
}
}
// ------------------------------------------------------------------------
@ -1338,6 +1404,15 @@ mod test {
assert!(ExtendedPoint::identity().is_identity());
}
#[test]
fn test_montgomery_u_is_neg_one_rejected() {
let fe_u: FieldElement = FieldElement::minus_one();
let u: CompressedMontgomeryU = CompressedMontgomeryU(fe_u.to_bytes());
let result: Option<ExtendedPoint> = u.decompress();
assert!(result.is_none());
}
#[bench]
fn bench_basepoint_mult(b: &mut Bencher) {
b.iter(|| ExtendedPoint::basepoint_mult(&A_SCALAR));
@ -1412,4 +1487,20 @@ mod test {
b.iter(| | p1.mult_by_pow_2(4) );
}
#[bench]
fn bench_compress_edwards(b: &mut Bencher) {
let mut rng: OsRng = OsRng::new().unwrap();
let p1: ExtendedPoint = ExtendedPoint::basepoint_mult(&Scalar::random(&mut rng));
b.iter(| | p1.compress() );
}
#[bench]
fn bench_compress_montgomery(b: &mut Bencher) {
let mut rng: OsRng = OsRng::new().unwrap();
let p1: ExtendedPoint = ExtendedPoint::basepoint_mult(&Scalar::random(&mut rng));
b.iter(| | p1.compress_montgomery() );
}
}