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Merge remote-tracking branch 'ebfull/sequential-montgomery-trick' into develop
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commit
11aa71fb8d
2 changed files with 83 additions and 74 deletions
73
src/field.rs
73
src/field.rs
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@ -142,58 +142,34 @@ impl FieldElement {
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/// Given a slice of public `FieldElements`, replace each with its inverse.
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///
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/// All input `FieldElements` **MUST** be nonzero.
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///
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/// This function is most efficient when the batch size (slice
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/// length) is a power of 2.
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#[cfg(any(feature = "alloc", feature = "std"))]
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pub fn batch_invert(inputs: &mut [FieldElement]) {
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// First, compute the product of all inputs using a product
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// tree:
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//
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// Inputs: [x_0, x_1, x_2]
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//
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// Tree:
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//
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// x_0*x_1*x_2*1 tree[1]
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// / \
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// x_0*x_1 x_2*1 tree[2,3]
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// / \ / \
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// x_0 x_1 x_2 1 tree[4,5,6,7]
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//
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// The leaves of the tree are the inputs. We store the tree in
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// an array of length 2*n, similar to a binary heap.
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//
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// To initialize the tree, set every node to 1, then fill in
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// the leaf nodes with the input variables. Finally, set every
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// non-leaf node to be the product of its children.
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// Montgomery’s Trick and Fast Implementation of Masked AES
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// Genelle, Prouff and Quisquater
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// Section 3.2
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let n = inputs.len().next_power_of_two();
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let mut tree = vec![FieldElement::one(); 2*n];
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tree[n..n+inputs.len()].copy_from_slice(inputs);
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for i in (1..n).rev() {
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tree[i] = &tree[2*i] * &tree[2*i+1];
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let n = inputs.len();
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let mut scratch = vec![FieldElement::one(); n];
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// Keep an accumulator of all of the previous products
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let mut acc = FieldElement::one();
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// Pass through the input vector, recording the previous
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// products in the scratch space
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for (input, scratch) in inputs.iter().zip(scratch.iter_mut()) {
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*scratch = acc;
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acc = &acc * input;
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}
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// The root of the tree is the product of all inputs, and is
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// stored at index 1. Compute its inverse.
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let allinv = tree[1].invert();
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// Compute the inverse of all products
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acc = acc.invert();
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// To compute y_i = 1/x_i, start at the i-th leaf node of the
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// tree, and walk up to the root of the tree, multiplying
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// `allinv` by each sibling. This computes
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//
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// y_i = y * (all x_j except x_i)
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//
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// using lg(n) multiplications for each y_i, taking n*lg(n) in
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// total.
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for i in 0..inputs.len() {
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let mut inv = allinv;
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let mut node = n + i;
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while node > 1 {
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inv *= &tree[node ^ 1];
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node = node >> 1;
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}
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inputs[i] = inv;
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// Pass through the vector backwards to compute the inverses
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// in place
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for (input, scratch) in inputs.iter_mut().rev().zip(scratch.into_iter().rev()) {
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let tmp = &acc * input;
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*input = &acc * &scratch;
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acc = tmp;
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}
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}
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@ -496,4 +472,9 @@ mod test {
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assert_eq!(one_bytes[i], 0);
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}
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}
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#[test]
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fn batch_invert_empty() {
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FieldElement::batch_invert(&mut []);
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}
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}
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@ -434,9 +434,6 @@ impl Scalar {
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/// *prove* that this is the case, you **SHOULD NOT USE THIS
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/// FUNCTION**.
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///
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/// This function is most efficient when the batch size (slice
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/// length) is a power of 2.
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///
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/// # Example
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///
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/// ```
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@ -474,38 +471,47 @@ impl Scalar {
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// Mark UnpackedScalars as zeroable.
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unsafe impl ZeroSafe for UnpackedScalar {}
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let n = inputs.len().next_power_of_two();
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let n = inputs.len();
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let one: UnpackedScalar = Scalar::one().unpack().to_montgomery();
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// Wrap the tree storage in a ClearOnDrop to wipe it when we
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// pass out of scope.
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let tree_vec = vec![one; 2*n];
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let mut tree = ClearOnDrop::new(tree_vec);
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// Wrap the scratch storage in a ClearOnDrop to wipe it when
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// we pass out of scope.
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let scratch_vec = vec![one; n];
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let mut scratch = ClearOnDrop::new(scratch_vec);
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for i in 0..inputs.len() {
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tree[n+i] = inputs[i].unpack().to_montgomery();
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// Keep an accumulator of all of the previous products
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let mut acc = Scalar::one().unpack().to_montgomery();
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// Pass through the input vector, recording the previous
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// products in the scratch space
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for (input, scratch) in inputs.iter_mut().zip(scratch.iter_mut()) {
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*scratch = acc;
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// Avoid unnecessary Montgomery multiplication in second pass by
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// keeping inputs in Montgomery form
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let tmp = input.unpack().to_montgomery();
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*input = tmp.pack();
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acc = UnpackedScalar::montgomery_mul(&acc, &tmp);
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}
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for i in (1..n).rev() {
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tree[i] = UnpackedScalar::montgomery_mul(&tree[2*i], &tree[2*i+1]);
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// acc is nonzero iff all inputs are nonzero
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debug_assert!(acc.pack() != Scalar::zero());
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// Compute the inverse of all products
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acc = acc.montgomery_invert().from_montgomery();
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// We need to return the product of all inverses later
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let ret = acc.pack();
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// Pass through the vector backwards to compute the inverses
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// in place
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for (input, scratch) in inputs.iter_mut().rev().zip(scratch.into_iter().rev()) {
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let tmp = UnpackedScalar::montgomery_mul(&acc, &input.unpack());
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*input = UnpackedScalar::montgomery_mul(&acc, &scratch).pack();
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acc = tmp;
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}
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// tree[1] is zero iff any of the inputs are zero.
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debug_assert!(tree[1].from_montgomery().pack() != Scalar::zero());
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let allinv = tree[1].montgomery_invert();
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for i in 0..inputs.len() {
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let mut inv = allinv;
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let mut node = n + i;
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while node > 1 {
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inv = UnpackedScalar::montgomery_mul(&inv, &tree[node ^1]);
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node = node >> 1;
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}
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inputs[i] = inv.from_montgomery().pack();
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}
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allinv.from_montgomery().pack()
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ret
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}
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/// Get the bits of the scalar.
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@ -1130,6 +1136,7 @@ mod test {
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assert_eq!(parsed, X);
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}
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#[cfg(debug_assertions)]
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#[test]
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#[should_panic]
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fn batch_invert_with_a_zero_input_panics() {
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@ -1138,4 +1145,25 @@ mod test {
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// This should panic in debug mode.
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Scalar::batch_invert(&mut xs);
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}
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#[test]
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fn batch_invert_empty() {
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assert_eq!(Scalar::one(), Scalar::batch_invert(&mut []));
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}
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#[test]
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fn batch_invert_consistency() {
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let mut x = Scalar::from_u64(1);
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let mut v1: Vec<_> = (0..16).map(|_| {let tmp = x; x = x + x; tmp}).collect();
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let v2 = v1.clone();
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let expected: Scalar = v1.iter().product();
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let expected = expected.invert();
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let ret = Scalar::batch_invert(&mut v1);
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assert_eq!(ret, expected);
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for (a, b) in v1.iter().zip(v2.iter()) {
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assert_eq!(a * b, Scalar::one());
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}
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}
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}
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